In the Leetcode Add Two Numbers problem solution in Java programming You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order, and each of their nodes contains a single digit. Add the two numbers and return the sum as a linked list.
You may assume the two numbers do not contain any leading zero, except the number 0 itself.
Leetcode Add Two Numbers problem solution in Java programming
class Solution {
public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
ListNode ans = new ListNode();
ListNode pointer = ans;
while(l1 != null && l2 != null){
//when overflow
if(l1.val + l2.val + pointer.val >= 10){
pointer.next = new ListNode(1);
}
//when no overflow
else{
if(l1.next != null || l2.next != null)
pointer.next = new ListNode(0);
}
pointer.val = ((l1.val + l2.val + pointer.val)%10);
pointer = pointer.next;
l1 = l1.next;
l2 = l2.next;
}
while(l1 != null){
//when overflow
if(l1.val + pointer.val >= 10){
pointer.next = new ListNode(1);
}
//when no overflow
else{
if(l1.next != null)
pointer.next = new ListNode(0);
}
pointer.val = ((l1.val + pointer.val)%10);
pointer = pointer.next;
l1 = l1.next;
}
while(l2 != null){
//when overflow
if(l2.val + pointer.val >= 10){
pointer.next = new ListNode(1);
}
//when no overflow
else{
if(l2.next != null)
pointer.next = new ListNode(0);
}
pointer.val = ((l2.val + pointer.val)%10);
pointer = pointer.next;
l2 = l2.next;
}
return ans;
}
}Also read,
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