# Leetcode Roman to Integer problem solution in Java

Feb 16, 2023

In the Leetcode Roman to Integer problem solution in Java programming Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M.

Symbol Value
I 1
V 5
X 10
L 50
C 100
D 500
M 1000
For example, 2 is written as II in Roman numeral, just two ones added together. 12 is written as XII, which is simply X + II. The number 27 is written as XXVII, which is XX + V + II.

Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not IIII. Instead, the number four is written as IV. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as IX. There are six instances where subtraction is used:

I can be placed before V (5) and X (10) to make 4 and 9.
X can be placed before L (50) and C (100) to make 40 and 90.
C can be placed before D (500) and M (1000) to make 400 and 900.
Given a roman numeral, convert it to an integer.

## Leetcode Roman to Integer problem solution in Java programming

``````class Solution {
public int romanToInt(String s) {

int result = 0;

for(int i = 0; i < s.length(); i++) {

char c = s.charAt(i);

if(c == 'I')
result = result + 1;

if(c == 'V')
result = result + 5;

if(c == 'X')
result = result + 10;

if(c == 'L')
result = result + 50;

if(c == 'C')
result = result + 100;

if(c == 'D')
result = result + 500;

if(c == 'M')
result = result + 1000;
}

for(int i = 0; i < s.length() - 1; i++) {

char c1 = s.charAt(i);
char c2 = s.charAt(i+1);

if (c1 == 'I' && (c2 == 'V' || c2 == 'X'))
result = result - 2;

if (c1 == 'X' && (c2 == 'L' || c2 == 'C'))
result = result - 20;

if (c1 == 'C' && (c2 == 'D' || c2 == 'M'))
result = result - 200;
}

return result;
}
}``````

#### By Neha Singhal

Hi, my name is Neha singhal a software engineer and coder by profession. I like to solve coding problems that give me the power to write posts for this site.